3.37 \(\int \frac{3+2 x}{\sqrt{-3-4 x-x^2} \left (3+4 x+2 x^2\right )} \, dx\)

Optimal. Leaf size=17 \[ \tanh ^{-1}\left (\frac{x}{\sqrt{-x^2-4 x-3}}\right ) \]

[Out]

ArcTanh[x/Sqrt[-3 - 4*x - x^2]]

_______________________________________________________________________________________

Rubi [A]  time = 0.0665603, antiderivative size = 17, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 32, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.062 \[ \tanh ^{-1}\left (\frac{x}{\sqrt{-x^2-4 x-3}}\right ) \]

Antiderivative was successfully verified.

[In]  Int[(3 + 2*x)/(Sqrt[-3 - 4*x - x^2]*(3 + 4*x + 2*x^2)),x]

[Out]

ArcTanh[x/Sqrt[-3 - 4*x - x^2]]

_______________________________________________________________________________________

Rubi in Sympy [A]  time = 18.129, size = 15, normalized size = 0.88 \[ \operatorname{atanh}{\left (\frac{x}{\sqrt{- x^{2} - 4 x - 3}} \right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((3+2*x)/(2*x**2+4*x+3)/(-x**2-4*x-3)**(1/2),x)

[Out]

atanh(x/sqrt(-x**2 - 4*x - 3))

_______________________________________________________________________________________

Mathematica [C]  time = 6.28269, size = 1057, normalized size = 62.18 \[ -\frac{i \left (-i+\sqrt{2}\right ) \tan ^{-1}\left (\frac{6 i \sqrt{2} x^4+8 x^4+6 i \sqrt{1-2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x^3+20 i \sqrt{2} x^3+52 x^3+24 i \sqrt{1-2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x^2+11 i \sqrt{2} x^2+112 x^2+33 i \sqrt{1-2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x-16 i \sqrt{2} x+92 x+18 i \sqrt{1-2 i \sqrt{2}} \sqrt{-x^2-4 x-3}-12 i \sqrt{2}+24}{8 \sqrt{2} x^4+6 i x^4+40 \sqrt{2} x^3+16 i x^3+58 \sqrt{2} x^2+19 i x^2+32 \sqrt{2} x+28 i x+6 \sqrt{2}+21 i}\right )}{2 \sqrt{1-2 i \sqrt{2}}}+\frac{\left (i+\sqrt{2}\right ) \tanh ^{-1}\left (\frac{6 \sqrt{2} x^4+8 i x^4+6 \sqrt{1+2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x^3+20 \sqrt{2} x^3+52 i x^3+24 \sqrt{1+2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x^2+11 \sqrt{2} x^2+112 i x^2+33 \sqrt{1+2 i \sqrt{2}} \sqrt{-x^2-4 x-3} x-16 \sqrt{2} x+92 i x+18 \sqrt{1+2 i \sqrt{2}} \sqrt{-x^2-4 x-3}-12 \sqrt{2}+24 i}{8 \sqrt{2} x^4-6 i x^4+40 \sqrt{2} x^3-16 i x^3+58 \sqrt{2} x^2-19 i x^2+32 \sqrt{2} x-28 i x+6 \sqrt{2}-21 i}\right )}{2 \sqrt{1+2 i \sqrt{2}}}+\frac{\left (i+\sqrt{2}\right ) \log \left (\left (-2 i x+\sqrt{2}-2 i\right )^2 \left (2 i x+\sqrt{2}+2 i\right )^2\right )}{4 \sqrt{1+2 i \sqrt{2}}}+\frac{\left (-i+\sqrt{2}\right ) \log \left (\left (-2 i x+\sqrt{2}-2 i\right )^2 \left (2 i x+\sqrt{2}+2 i\right )^2\right )}{4 \sqrt{1-2 i \sqrt{2}}}-\frac{\left (-i+\sqrt{2}\right ) \log \left (\left (2 x^2+4 x+3\right ) \left (2 i \sqrt{2} x^2+2 x^2-2 \sqrt{2 \left (1-2 i \sqrt{2}\right )} \sqrt{-x^2-4 x-3} x+8 i \sqrt{2} x+4 x-2 \sqrt{2 \left (1-2 i \sqrt{2}\right )} \sqrt{-x^2-4 x-3}+6 i \sqrt{2}+3\right )\right )}{4 \sqrt{1-2 i \sqrt{2}}}-\frac{\left (i+\sqrt{2}\right ) \log \left (\left (2 x^2+4 x+3\right ) \left (-2 i \sqrt{2} x^2+2 x^2-2 \sqrt{2 \left (1+2 i \sqrt{2}\right )} \sqrt{-x^2-4 x-3} x-8 i \sqrt{2} x+4 x-2 \sqrt{2 \left (1+2 i \sqrt{2}\right )} \sqrt{-x^2-4 x-3}-6 i \sqrt{2}+3\right )\right )}{4 \sqrt{1+2 i \sqrt{2}}} \]

Antiderivative was successfully verified.

[In]  Integrate[(3 + 2*x)/(Sqrt[-3 - 4*x - x^2]*(3 + 4*x + 2*x^2)),x]

[Out]

((-I/2)*(-I + Sqrt[2])*ArcTan[(24 - (12*I)*Sqrt[2] + 92*x - (16*I)*Sqrt[2]*x + 1
12*x^2 + (11*I)*Sqrt[2]*x^2 + 52*x^3 + (20*I)*Sqrt[2]*x^3 + 8*x^4 + (6*I)*Sqrt[2
]*x^4 + (18*I)*Sqrt[1 - (2*I)*Sqrt[2]]*Sqrt[-3 - 4*x - x^2] + (33*I)*Sqrt[1 - (2
*I)*Sqrt[2]]*x*Sqrt[-3 - 4*x - x^2] + (24*I)*Sqrt[1 - (2*I)*Sqrt[2]]*x^2*Sqrt[-3
 - 4*x - x^2] + (6*I)*Sqrt[1 - (2*I)*Sqrt[2]]*x^3*Sqrt[-3 - 4*x - x^2])/(21*I +
6*Sqrt[2] + (28*I)*x + 32*Sqrt[2]*x + (19*I)*x^2 + 58*Sqrt[2]*x^2 + (16*I)*x^3 +
 40*Sqrt[2]*x^3 + (6*I)*x^4 + 8*Sqrt[2]*x^4)])/Sqrt[1 - (2*I)*Sqrt[2]] + ((I + S
qrt[2])*ArcTanh[(24*I - 12*Sqrt[2] + (92*I)*x - 16*Sqrt[2]*x + (112*I)*x^2 + 11*
Sqrt[2]*x^2 + (52*I)*x^3 + 20*Sqrt[2]*x^3 + (8*I)*x^4 + 6*Sqrt[2]*x^4 + 18*Sqrt[
1 + (2*I)*Sqrt[2]]*Sqrt[-3 - 4*x - x^2] + 33*Sqrt[1 + (2*I)*Sqrt[2]]*x*Sqrt[-3 -
 4*x - x^2] + 24*Sqrt[1 + (2*I)*Sqrt[2]]*x^2*Sqrt[-3 - 4*x - x^2] + 6*Sqrt[1 + (
2*I)*Sqrt[2]]*x^3*Sqrt[-3 - 4*x - x^2])/(-21*I + 6*Sqrt[2] - (28*I)*x + 32*Sqrt[
2]*x - (19*I)*x^2 + 58*Sqrt[2]*x^2 - (16*I)*x^3 + 40*Sqrt[2]*x^3 - (6*I)*x^4 + 8
*Sqrt[2]*x^4)])/(2*Sqrt[1 + (2*I)*Sqrt[2]]) + ((-I + Sqrt[2])*Log[(-2*I + Sqrt[2
] - (2*I)*x)^2*(2*I + Sqrt[2] + (2*I)*x)^2])/(4*Sqrt[1 - (2*I)*Sqrt[2]]) + ((I +
 Sqrt[2])*Log[(-2*I + Sqrt[2] - (2*I)*x)^2*(2*I + Sqrt[2] + (2*I)*x)^2])/(4*Sqrt
[1 + (2*I)*Sqrt[2]]) - ((-I + Sqrt[2])*Log[(3 + 4*x + 2*x^2)*(3 + (6*I)*Sqrt[2]
+ 4*x + (8*I)*Sqrt[2]*x + 2*x^2 + (2*I)*Sqrt[2]*x^2 - 2*Sqrt[2*(1 - (2*I)*Sqrt[2
])]*Sqrt[-3 - 4*x - x^2] - 2*Sqrt[2*(1 - (2*I)*Sqrt[2])]*x*Sqrt[-3 - 4*x - x^2])
])/(4*Sqrt[1 - (2*I)*Sqrt[2]]) - ((I + Sqrt[2])*Log[(3 + 4*x + 2*x^2)*(3 - (6*I)
*Sqrt[2] + 4*x - (8*I)*Sqrt[2]*x + 2*x^2 - (2*I)*Sqrt[2]*x^2 - 2*Sqrt[2*(1 + (2*
I)*Sqrt[2])]*Sqrt[-3 - 4*x - x^2] - 2*Sqrt[2*(1 + (2*I)*Sqrt[2])]*x*Sqrt[-3 - 4*
x - x^2])])/(4*Sqrt[1 + (2*I)*Sqrt[2]])

_______________________________________________________________________________________

Maple [B]  time = 0.015, size = 94, normalized size = 5.5 \[ -{\frac{\sqrt{3}\sqrt{4}}{6}\sqrt{3\,{\frac{{x}^{2}}{ \left ( -3/2-x \right ) ^{2}}}-12}{\it Artanh} \left ( 3\,{\frac{x}{-3/2-x}{\frac{1}{\sqrt{3\,{\frac{{x}^{2}}{ \left ( -3/2-x \right ) ^{2}}}-12}}}} \right ){\frac{1}{\sqrt{{1 \left ({{x}^{2} \left ( -{\frac{3}{2}}-x \right ) ^{-2}}-4 \right ) \left ( 1+{x \left ( -{\frac{3}{2}}-x \right ) ^{-1}} \right ) ^{-2}}}}} \left ( 1+{x \left ( -{\frac{3}{2}}-x \right ) ^{-1}} \right ) ^{-1}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((3+2*x)/(2*x^2+4*x+3)/(-x^2-4*x-3)^(1/2),x)

[Out]

-1/6*3^(1/2)*4^(1/2)/((x^2/(-3/2-x)^2-4)/(1+x/(-3/2-x))^2)^(1/2)/(1+x/(-3/2-x))*
(3*x^2/(-3/2-x)^2-12)^(1/2)*arctanh(3*x/(-3/2-x)/(3*x^2/(-3/2-x)^2-12)^(1/2))

_______________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{2 \, x + 3}{{\left (2 \, x^{2} + 4 \, x + 3\right )} \sqrt{-x^{2} - 4 \, x - 3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((2*x + 3)/((2*x^2 + 4*x + 3)*sqrt(-x^2 - 4*x - 3)),x, algorithm="maxima")

[Out]

integrate((2*x + 3)/((2*x^2 + 4*x + 3)*sqrt(-x^2 - 4*x - 3)), x)

_______________________________________________________________________________________

Fricas [A]  time = 0.288099, size = 76, normalized size = 4.47 \[ -\frac{1}{4} \, \log \left (-\frac{2 \, \sqrt{-x^{2} - 4 \, x - 3} x + 4 \, x + 3}{x^{2}}\right ) + \frac{1}{4} \, \log \left (\frac{2 \, \sqrt{-x^{2} - 4 \, x - 3} x - 4 \, x - 3}{x^{2}}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((2*x + 3)/((2*x^2 + 4*x + 3)*sqrt(-x^2 - 4*x - 3)),x, algorithm="fricas")

[Out]

-1/4*log(-(2*sqrt(-x^2 - 4*x - 3)*x + 4*x + 3)/x^2) + 1/4*log((2*sqrt(-x^2 - 4*x
 - 3)*x - 4*x - 3)/x^2)

_______________________________________________________________________________________

Sympy [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{2 x + 3}{\sqrt{- \left (x + 1\right ) \left (x + 3\right )} \left (2 x^{2} + 4 x + 3\right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((3+2*x)/(2*x**2+4*x+3)/(-x**2-4*x-3)**(1/2),x)

[Out]

Integral((2*x + 3)/(sqrt(-(x + 1)*(x + 3))*(2*x**2 + 4*x + 3)), x)

_______________________________________________________________________________________

GIAC/XCAS [A]  time = 0.274404, size = 132, normalized size = 7.76 \[ \frac{1}{2} \,{\rm ln}\left (\frac{2 \,{\left (\sqrt{-x^{2} - 4 \, x - 3} - 1\right )}}{x + 2} + \frac{3 \,{\left (\sqrt{-x^{2} - 4 \, x - 3} - 1\right )}^{2}}{{\left (x + 2\right )}^{2}} + 1\right ) - \frac{1}{2} \,{\rm ln}\left (\frac{2 \,{\left (\sqrt{-x^{2} - 4 \, x - 3} - 1\right )}}{x + 2} + \frac{{\left (\sqrt{-x^{2} - 4 \, x - 3} - 1\right )}^{2}}{{\left (x + 2\right )}^{2}} + 3\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((2*x + 3)/((2*x^2 + 4*x + 3)*sqrt(-x^2 - 4*x - 3)),x, algorithm="giac")

[Out]

1/2*ln(2*(sqrt(-x^2 - 4*x - 3) - 1)/(x + 2) + 3*(sqrt(-x^2 - 4*x - 3) - 1)^2/(x
+ 2)^2 + 1) - 1/2*ln(2*(sqrt(-x^2 - 4*x - 3) - 1)/(x + 2) + (sqrt(-x^2 - 4*x - 3
) - 1)^2/(x + 2)^2 + 3)